[백준] Archivist (20232)(kotlin)
문제 설명
입력 및 출력
» 입력
The only line of input contains a single integer y ( 1995≤y≤2019 ), denoting the year. You don’t need to process year numbers less than 1995 or greater than 2019 , or incorrect year formats. It is guaranteed that you will be given a number between 1995 and 2019 , inclusive.
» 출력
Print the winner of the contest in year y exactly in the same format as in the list above.
예제 입출력
입력 | 출력 |
---|---|
2006 | PetrSU, ITMO |
2019 | ITMO |
2018 | SPbSU |
2003 | ITMO |
문제 풀이1
import java.util.Scanner
fun main(args: Array<String>) = with(Scanner(System.`in`)){
val map = mutableMapOf<String, String>()
map.put("1995", "ITMO")
map.put("1996", "SPbSU")
map.put("1997", "SPbSU")
map.put("1998", "ITMO")
map.put("1999", "ITMO")
map.put("2000", "SPbSU")
map.put("2001", "ITMO")
map.put("2002", "ITMO")
map.put("2003", "ITMO")
map.put("2004", "ITMO")
map.put("2005", "ITMO")
map.put("2006", "PetrSU, ITMO")
map.put("2007", "SPbSU")
map.put("2008", "SPbSU")
map.put("2009", "ITMO")
map.put("2010", "ITMO")
map.put("2011", "ITMO")
map.put("2012", "ITMO")
map.put("2013", "SPbSU")
map.put("2014", "ITMO")
map.put("2015", "ITMO")
map.put("2016", "ITMO")
map.put("2017", "ITMO")
map.put("2018", "SPbSU")
map.put("2019", "ITMO")
println(map[next()])
}